Selenium WebDriver – How To Find Broken Links On a Page

Overview:

In this article, we will see how we could use Selenium WebDriver to find broken links on a webpage.

Utility Class:

To demonstrate how it works, I would be using below simple utility. This below method simply returns the HTTP response code the given URL.

public class LinkUtil {

    // hits the given url and returns the HTTP response code
    public static int getResponseCode(String link) {
        URL url;
        HttpURLConnection con = null;
        Integer responsecode = 0;
        try {
            url = new URL(link);
            con = (HttpURLConnection) url.openConnection();
            responsecode = con.getResponseCode();
        } catch (Exception e) {
            // skip
        } finally {
            if (null != con)
                con.disconnect();
        }
        return responsecode;
    }

}

Usage:

Rest is simple.  Find all the elements which has the href / src attribute and by using the above utility class, we could collect the response codes for all the links and groups them based on the response codes.

driver.get("https://www.yahoo.com");

Map<Integer, List<String>> map = driver.findElements(By.xpath("//*[@href]")) 
                .stream()                             // find all elements which has href attribute & process one by one
                .map(ele -> ele.getAttribute("href")) // get the value of href
                .map(String::trim)                    // trim the text
                .distinct()                           // there could be duplicate links , so find unique
                .collect(Collectors.groupingBy(LinkUtil::getResponseCode)); // group the links based on the response code

Now we could access the urls based on the response code we are interested in.

map.get(200) // will contain all the good urls
map.get(403) // will contain all the 'Forbidden' urls   
map.get(404) // will contain all the 'Not Found' urls   
map.get(0) // will contain all the unknown host urls

We can even simplify this – just partition the urls if the response code is 200 or not.

Map<Boolean, List<String>> map= driver.findElements(By.xpath("//*[@href]"))  // find all elements which has href attribute
                  .stream()
                  .map(ele -> ele.getAttribute("href"))   // get the value of href
                  .map(String::trim)                      // trim the text
                  .distinct()                             // there could be duplicate links , so find unique
                  .collect(Collectors.partitioningBy(link -> LinkUtil.getResponseCode(link) == 200)); // partition based on response code

Simply we could access the map to list all the bad urls as shown here.

map.get(true) // will contain all the good urls
map.get(false) // will contain all the bad urls

Print all the bad URLs.

map.get(false)
   .stream()
   .forEach(System.out::println);

 

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